Answer:
D) EAC is equilateral triangle
Explanation:
Given :
AEC is a triangle in which B∈ AC and D∈EC
Such that,
∠ABE = 90°,
∠ADE = 90°,
Also, BC = CD
We have to prove that :
Δ ABE is congruent to Δ EDA
Proof :
If EAC is an equilateral triangle,
By the property of equilateral triangle,
EA = AC = EC
If AC = EC
⇒ AB + BC = ED + CD
⇒ AB + CD = ED + CD
⇒ AB = ED
Also, AE = AE ( common segment )
Now, if in two right triangles hypotenuse are equal and any corresponding legs are equal,
Then, the other legs must be equal,
That is, BE = DA,
Hence, by SSS postulate of congruence,
Δ ABE ≅ Δ EDA
Therefore, option D is correct.