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An ideal solenoid having a coil density of 5000 turns per meter is 10 cm long and carries a current of 4.0

a. what is the strength of the magnetic field at its center?

User Florian Bw
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1 Answer

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The rule that is used to get the strength of magnetic field at the center of solenoid (B) is:
B = µ x n x I where:
µ is the permeability of the medium where the solenoid is based. In this problem, the medium is air which means that µ = µ o = 4 pi x 10^-7 Tm/A
I is the current passing (I = 4 amperes)
n is the number of turns per unit length (5000 turns)

Substituting in the mentioned equation, we find that:
B = 4 x 3.14 x 10^-7 x 5000 x 4 = 25.132 mT
User Wolfsbane
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