Question

What is the vertex of y=-5(x-5)^2+1125

Answer 1

`\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} y=a(x-{{ h}})^2+{{ k}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\ %y=-5(x-5)^2+1125 \begin{array}{llcll} y=-5(x-&5)^2&+1125\\ &\uparrow &\uparrow \\ &h&k \end{array}`