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Given f(x), use Remainder Theorem to find f(4). f (x) = 2x^3 – 11x^2 + 7x - 5

User Jxstanford
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f(x)=2x^3-11x^2+7x-5

To find f(4) you divide the given polynomial into (x-4):

To divide:

1. Divide the first term of the dividend by the highest term of the divisor:


(2x^3)/(x)=2x^2

2. Multiply the divisor by the result:


2x^2(x-4)=2x^3-8x^2

3. Substract the product in step 2 from the appropiat terms of the dividend (when you substract the symbols change) (then bring down the next term from the dividend)

4. Repeat previous steps:


(-3x^2)/(x)=-3x
-3x(x-4)=-3x^2+12x
(-5x)/(x)=-5
-5(x-4)=-5x+20

As the remainder is -25:


f(4)=-25

Given f(x), use Remainder Theorem to find f(4). f (x) = 2x^3 – 11x^2 + 7x - 5-example-1
Given f(x), use Remainder Theorem to find f(4). f (x) = 2x^3 – 11x^2 + 7x - 5-example-2
Given f(x), use Remainder Theorem to find f(4). f (x) = 2x^3 – 11x^2 + 7x - 5-example-3
Given f(x), use Remainder Theorem to find f(4). f (x) = 2x^3 – 11x^2 + 7x - 5-example-4
Given f(x), use Remainder Theorem to find f(4). f (x) = 2x^3 – 11x^2 + 7x - 5-example-5
User Danielnixon
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