Question

The widrh of a rectangle is w yards and the length of a rectangle is (6w-4) yards. The perimeter of the rectangle is given by the algebraic expression 2w+2(6w-4). Simplify the algebraic expression 2w+2(6w-4) and determine the perimeter of a rectangle whose width w is 4 yards

Answer 1

p=2w+2(6w-4) can be simplified to:

p=2w+12w-8

p=14w-8

if w=4

p=14(4)-8

p=56-8 = 48 yards

check:

w = 4

length = 6w-4= 6(4)-4 = 24-4=20

perimeter = 4*2 + 20*2 = 8+40 = 48

it checks out, perimeter = 48 yards