1 Answer

Middlestump · Answer 1 · 2018-09-24T12:49:07+0000

((2f^4)^2*f^3)/(6f^9)

pertinent rules of exponents:

(a^b)^c=a^(b*c), (a^b)(a^c)=a^(b+c), and (a^b)/(a^c)=a^(b-c) so

(2f^(4*2)*f^3)/(6f^9)

(2f^8*f^3)/(6f^9)

(2f^(8+3))/(6f^9)

(2f^11)/(6f^9)

(2/6)(f^11/f^9)

(1/3)(f^(11-9)

(1/3)(f^2)

(f^2)/3

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