Question

7.Calculate the velocity of Cart 1 after the collision.A 0.0 m/sB. 5.5 m/sC -2.2 m/sD. +6.5 m/s

Answer 1

Given data

*The mass of cart 1 is 2.5 kg

*The mass of cart 2 is 4 kg

*The speed of the cart 1 before the collision is 5 m/s

*The speed of the cart 2 before the collision is -1.5 m/s

*The speed of the cart 2 after the collision is 3 m/s

The formula for the velocity of the cart 1 is given by the conservation of momentum as

`\begin{gathered} P_i=P_f \\ m_1u_1+m_2u_{2_{}}=m_1v_1+m_2v_2 \end{gathered}`

Substitute the known values in the above expression as

`\begin{gathered} 2.5*5+4*-1.5=2.5* v_1+4*3_{} \\ 6.5=2.5v_1+12 \\ v_1=-2.2\text{ m/s} \end{gathered}`

Thus, the velocity of Cart 1 after the collision is -2.2 m/s and the correct answer is (C)