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How many ways can we put 7 adults and 3 kids in line (where order matters) so that no two kids are next to each other?

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Given that the order matters in this question, we shall apply the concept of permutation rather than computation. Thus, the number of ways in which that we can put 7 adults and 3 kids in line will be:
7P3
=210
There are more than 210 ways we can do this.
User Essan Parto
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