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How many moles of ions are released when 0.27 mol of cobalt (ii) chloride, cocl2, is dissolved in water?

1 Answer

5 votes
CoCl₂(s) → Co²⁺(aq) + 2Cl⁻(aq)

n(CoCl₂)=0.27 mol

n(Co²⁺)=n(CoCl₂)
n(Cl⁻)=2n(CoCl₂)

n=n(Co²⁺)+n(Cl⁻)=3n(CoCl₂)

n=3*0.27=0.81 mol
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