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A boy jumps at a speed of 20.0 m/s at an angle of 25.0o above the horizontal. what is the horizontal component of the boy's velocity?
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A boy jumps at a speed of 20.0 m/s at an angle of 25.0o above the horizontal. what is the horizontal component of the boy's velocity?

User Fausto Alonso
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Given:
Launch velocity = 20 m/s
Launch angle = 25° above he horizontal.

The horizontal component of velocity is by definition
Vx = 20*cos(25°) = 18.13 m/s

Answer: 18.13 m/s (nearest hundredth)
A boy jumps at a speed of 20.0 m/s at an angle of 25.0o above the horizontal. what-example-1
User Tarannum
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