Ayana has $20.95 in quarters and dimes. If she has 103 coins in all. find the number of quarters and dimes. * SHE HAS 103 COINS IN ALL!
Let
x -----> the number of quarters
y ----> the number of dimes
we have that
x+y=103
x=103-y ------> equation A
Remember that
1 quarter=$0.25
1 dime=$0.10
so
0.25x+0.10y=20.95 ------> equation B
Solve the system of equations
substitute equation A in equation B
0.25(103-y)+0.10y=20.95
solve for y
25.75-0.25y+0.10y=20.95
0.15y=25.75-20.95
0.15y=4.8
y=32
Find the value of x
x=103-32
x=71
therefore
the answer is
71 quarters and 32 dimes