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What is the sum of the integers between the square root of 12 and 40?

User Jim Lewis
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1 Answer

4 votes
1.

the closest perfect squares of 12 are 9 and 16,

that is 9<12<16

so

√(9)\ \textless \ √(12)\ \textless \ √(16)


3\ \textless \ √(12)\ \textless 4

this means,
√(12) is 3 point something...


2.

similarly

36<40<49

so


√(36)\ \textless \ √(40)\ \textless \ √(49)


6\ \textless \ √(40)\ \textless \ 7

which means
√(40) is 6 point something...

3.

the sum of the integers between the square root of 12 and 40 is the sum of 4, 5 and 6, since 4 is the smallest integer after root 12, and 6 the greatest integer to before root of 40.


Answer: 15
User Vinoths
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