An acute angle θ is in a right triangle with sin θ = seven eighths. What is the value of cot θ? ANSWERS square root of fifteen divided by eight eight divided by the square root …

Draw a right triangle ABC, with m(CAB)=∅.

Let CB=7 units, AC=8 units, so by the Pythagorean theorem:

$AB= \sqrt{ AC^(2) - BC^(2) }= \sqrt{ 8^(2) - 7^(2) }= √(64-49) = √(15)$ (units)

so we have drawn a triangle where sin∅=7/8

in this triangle, cot∅=(adjacent side)/(opposite side)=
( √(15) )/(7)