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Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Check all that apply.

A=1 ≥ 2x
B=6x ≥ 3 + 8x – 4
and on a graph
.5 shaded to the left
- .5 shaded to the right
.5 shaded to the right

User PeteUK
by
6.0k points

2 Answers

4 votes

The correct answers are:

A) 1 ≥ 2x ; B) 6x ≥ 3 + 8x – 4 ; and .5 shaded to the left

Step-by-step explanation:

Our inequality given is 6x ≥ 3 + 4(2x - 1). First we use the distributive property:

6x ≥ 3 + 4(2x) + 4(-1)

6x ≥ 3 + 8x - 4

This means A is correct.

Next we can subtract 8x from each side:

6x-8x ≥ 3+8x-4-8x

-2x ≥ 3-4

-2x ≥ -1

Divide both sides by -1 (remember to flip the inequality symbol):

-2x/-1 ≥ -1/-1

2x ≤ 1

This can also be written as 1 ≥ 2x, so B is correct.

To finish solving this, divide both sides by 2:

2x/2 ≤ 1/2

x ≤ 0.5

To graph this, we circle 0.5 and fill it in (since it is less than or equal to), and shade to the left (since it is less than).

User JohnKoz
by
6.5k points
3 votes

checking all that apply the correct answers would be A B and C

User Izzie
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5.7k points