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Jacob wants to use an elevator to carry identical packages having the same weight. Each package weighs 3 pounds and Jacob weighs 99 pounds. If the elevator can carry a maximum of 300 pounds at a time, which inequality shows the maximum number of packages, n, that Jacob can carry with himself in the elevator if he is the only passenger?

2 Answers

2 votes

Answer:

It would be n ≤ 67

Explanation:

Hope this helps! I took the test btw and got it correct! :)

User GullerYA
by
6.5k points
5 votes

Answer:

The required inequality that shows the maximum number of packages is
n\leq 67.

Explanation:

Consider the provided information.

Each package weighs 3 pounds and Jacob weighs 99 pounds.

let n is the maximum number of package that Jacob can carry with himself in the elevator.

Thus, the total weight of Jacob while having n packages on the elevator is:


3n+99

The elevator can carry a maximum of 300 pounds at a time, therefore.


3n+99\leq 300

Now, subtract 99 from both sides and divide the obtained inequality with 3.


3n+99-99\leq 300-99


3n\leq 201


(3n)/(3)\leq (201)/(3)


n\leq 67

Thus, the Jacob can carry maximum 67 packages.

Hence, the required inequality that shows the maximum number of packages is
n\leq 67.

User Bkaankuguoglu
by
6.7k points
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