Question

Hillary rolls 2 number cubes numbered 1 through 6 while playing her favorite board game. She will get a second turn if she rolls a sum that is an odd number greater than 10. What are Hillary's chances of getting a second turn when she rolls the number cubes?

Answer 1

There is only one odd sum greater than 10 for a pair of dice, 11, and there are only two ways to roll that, a 5 and 6 or a 6 and 5.

P(11)=(2/6)(1/6)

P(11)=2/36

P(11)=1/18

Answer 2

The sample space = {36} total outcomes:
Te odd sum greater than 10 is:
either 5 + 6 = 11 or 6 + 5 =11

to get 5 & 6, P= 1/36
OR to get 6 & 5, P = 1/36
In "either or" you will add the probabilities"

P(to get a chance of getting a second turn)=1/36+1/36 = 2/36 = 1/18=0.0555