Question

Eight two-person teams are participating in a three-legged race. Find the number of orders in which all 8 teams can finish the race.

Answer 1

thx for points man

Explanation:

Answer 2

Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28

Answer: 28