Eight two-person teams are participating in a three-legged race. Find the number of orders in which all 8 teams can finish the race.

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asked Sep 13, 2018 166k views

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Amit Desale · Answer 1 · 2018-09-20T12:27:00+0000

Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28

Answer: 28

Eight two-person teams are participating in a three-legged race. Find the number of orders in which all 8 teams can finish the race.

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