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What are the real zeros of x^3 + 4x^2 − 9x − 36
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What are the real zeros of x^3 + 4x^2 − 9x − 36

User Faraz Khonsari
by
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2 Answers

2 votes

Answer:

x = −3, 3, −4

Explanation:

User Riteshmeher
by
5.9k points
4 votes
x3 + 4x2 -9x -36
[x3 + 4x2] -9 [ x+4]
take x2 common factor from first praket
x2[x+4] -9 [x+4]
= [x+4] *[x2 -9]
so the zeros of this equation are -4 , 3, -3
User GuyIncognito
by
5.8k points
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