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Factor k 2 + 13k + 12.

2 Answers

6 votes
Simplifying k2 + -13k + 12 = 0
Reorder the terms: 12 + -13k + k2 = 0
Solving 12 + -13k + k2 = 0
Solving for variable 'k'.
Factor a trinomial. (1 + -1k)(12 + -1k) = 0
User Treefrog
by
8.4k points
4 votes

Answer:

The factors of the given polynomial are : (k + 1)(k + 12)

Explanation:

The quadratic equation which is needed to be factorized is given as :

k² + 13k + 12

In order to factorize this, arrange 13k in such a way that the product of its factors equals to 12k² ⇒ 13k = 12k + k

⇒ k² + 13k + 12

⇒ k² + k + 12k + 12

⇒ k(k + 1) + 12(k + 1)

⇒ (k + 1)(k + 12)

Hence, The factors of the given polynomial are : (k + 1)(k + 12)

User Hihikomori
by
8.8k points