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Can anyone help me with this:

image

1 Answer

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\displaystyle \int (4x-8)/(x^2-4x-3)\, dx=\\ 2\int (2x-4)/(x^2-4x-3)\, dx=(*)\\\\\\ \int (f'(x))/(f(x))=\ln(f(x))+C\\\\\\ (*)=2\ln(x^2-4x-3)+C
User Strickland
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