Question

Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?

Answer 1

d = dimes

q = quarters

d=10+q

0.25q +0.10d = 3.45

0.25q + 0.10(10+q) = 3.45

0.25q + 1 +0.10q =3.45

0.35q=2.45

q = 2.45/0.35 = 7

d = 10+7 =17

0.25*7=1.75, 17*0.10 = 1.70, 1.75+1.70 = 3.45

she has 7 quarters and 17 dimes for a total of 24 coins