In this item, we have the mean incubation period of 23 days and the standard deviation is 22 days. We use z-score to determine the unknown in each of the items.
(a) less than 21 days.
z-score = (23 - 21) / 22 = 1/11
This translates to a percentage of 53.6%
(b) z-score for 19 days.
z-score = (23 - 19) / 22 = 2/11
This translates to a percentage of 57.2%.
z-score for 23 days.
z-score = (23 - 23)/ 22 = 0
This translates to a percentage of 50%.
The difference between the two numbers is only 7.2%
(c) z-score of 25.
z-score = (23 - 25)/ 22 = -1/11
This translates to a percentage of 42.3%.
Then, subtract this value from 100 to give us the final answer of 57.2%.