Question

If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

the quantity of 3 times a all over b
b over the quantity 3 times a
3 over the quantity a times b
3ab

Answer 1

Option the quantity of
`3` times a all over b

Explanation:

we know that

The area of rectangle is equal to

`A=LW`

where

L is the length side of rectangle

W is the width side of rectangle

In this problem we have

`A=24a^(2)b\ units^(2)`

`L=8ab^(2)\ units`

Remember that

`W=(A)/(L)`

substitute

`W=(24a^(2)b)/(8ab^(2))=(3a)/(b)\ units`