92.0k views
1 vote
What is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? y − 5 = −3(x + 2) y − 5 = 3(x + 2) y − 11 = −3(x − 2) y − 11 = −3(x + 2)

User FredBones
by
7.9k points

2 Answers

3 votes
hello :

Hello : let A(0,5) B(-2,11)
the slope is : (YB - YA)/(XB -XA)
(11-5)/(-2-0) = 6/(-2)
the slope is : -3

the equation in point-slope form of the line is : y-11 = -3(x+2)
User Gdoug
by
8.4k points
1 vote

Answer:
y-11=-3(x+2)


Explanation:

Given points : (0, 5) and (−2, 11)

Slope of the line passing through given points .


m=(y_2-y_1)/(x_2-x_1)=(11-5)/(-2-0)=(6)/(-2)=-3

Thus, slope of line passing through given points m=-3

We know that the equation of a line passing through points
(x_0,y_0) with slope 'm' is
(y-y_0)=m(x-x_0)

Thus, equation of a line passing through (−2, 11) with slope m=-3 will be


(y-11)=(-3)(x-(-2))\\\Rightarrow\ y-11=-3(x+2)

Hence, the equation of line is
y-11=-3(x+2)

User Maersu
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories