Question

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, what is the probability you will choose a consonant and then a vowel?

Answer 1

28+12=40


`P(C,V)=(12)/(40) * (28)/(40)\\\\ = (12 \ / \ 4)/(40 \ / \ 4) * (28 \ / \ 4)/(40 \ / \ 4) \\\\ = (3)/(10) * (7)/(10) \\\\ =(21)/(100)=0.21`

Answer:

`P(C,V)=0.21`

Answer 2

With replacement:

P(C,V)=(12/40)(28/40)

P(C,V)=336/1600

P(C,V)=21/100