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In the triangle below, what ratio is sin θ?

In the triangle below, what ratio is sin θ?-example-1
User Metafaniel
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2 Answers

3 votes
Bringing to mind SOHCAHTOA, we remember that the sine is the opposite divided by the hypotenuse.
Thus, our answer is
$(36)/(39)=\boxed{(12)/(13)}$.
User Bala
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3 votes

Answer: The required ratio is
(12)/(13).

Step-by-step explanation: In the given triangle, we are to find the ratio of sinθ.

We know that

in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.

For the given right-angled triangle, we get


\sin\theta=(perpendicular)/(hypotenuse)\\\\\\\Rightarrow \sin\theta=(36)/(39)\\\\\\\Rightarrow \sin\theta=(12)/(13).

Thus, the required ratio is
(12)/(13).

User Lloyd
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