Question

What is the center of a circle given by the equation (x-3)2+(y-9)2=16

Answer 1

The answer is : y = - 1x + 28


how I did it


(x-3)2+(y-9)2=16


1x - 3 times 2 + 1y -9 times 2 = 16


1x - 6 + 1y -18 =16
+6 +6

1x + 1y -12 = 16
+12 +12

1x + 1y = 28
-1x -1x

1y = -1x + 28
/1 /1 /1

y = - 1x + 28 or y = - x + 28