The tan(-x) is the same thing as -tan(x). The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
![[cos(x)][tan(-x)]](https://img.qammunity.org/2018/formulas/mathematics/high-school/n30hy3iy920dol0zxg8nxfvafvd93bna3u.png)
is the same as
![[cos(x)][ -(sin(x))/(cos(x))]](https://img.qammunity.org/2018/formulas/mathematics/high-school/qf8022z28zsx5hcol67fpft9c08hvkvefc.png)
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.