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The quadratic formula gives which roots for the equation 2x^2+7x+-2

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The quadratic expression is given
2x^(2) +7x-2 where the constants are


a=2

b=7

c=-2

Quadratic formula to find the roots is given as

x₁,₂ = [-b plus minus √(b)²-4ac)] ÷ 2a

Substitute a, b, and c from our expression we have

x₁,₂ = [-7 plus minus √(7)²-(4×2×-2)] ÷ 2(2)
x₁,₂ = [-7 plus minus√65] ÷ 4

from here we'll work out x₁ and x₂ separately

x₁ = (-7+√65) ÷ 4 = 0.266 (round to 3 dp)
x₂ = (-7-√65) ÷ 4 = -3.766 (round to 3 dp)



User Ioan Agopian
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