You can do a very quick estimation by telling the ~ 26% is close to 25%, end then two half-life have passed: one from 100% to 50% concentration, and other from 50% to 25% concentration. So, 2 * 1.25 billion years = 2.50 billion years.
The answer, then is that the fossil is 2.50 by old.
Given that this method has an accuracy of +/- 10% this answer is good enough.
For didactical purposes, I am goint to show you the exact procedure.
C = Co * e^ (- kt)
Half-life time => C = Co / 2
=> C / Co = (1/2) = e ^ (-kt)
=> -kt = ln(1/2) => kt = ln(2)
t = 1.25 by => k (1.25) = ln(2) => k = ln(2) / 1.25 = 0.5545
=> C/Co = e ^ (-kt)
In the problem C/Co = 26/100 => 0.26 = e^ (-0.5545t)
=> -0.5545t = ln (0.26)
=> t = - ln (0.26) / 0.5545 = 2.43 by.
So with the exact procedure you obtain 2.43 by while with the estimation that ~26% is close to 25% you obtain 2.50 by.