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A basketball player makes 39% of her shots from the free throw line. suppose that each of her shots can be considered independent and that she takes 5 shots. let x = the number of shots that she makes. what is the standard deviation for x?

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Answer: 1.09

Explanation:

Given : A basketball player makes 39% of her shots from the free throw line.

i.e. Proportion of her shots from the free throw line: p= 0.39

We assume that each of her shots can be considered independent .

She takes 5 shots.

i.e. Number of trials : n= 5

Let x = the number of shots that she makes.

Then , the standard deviation for x will be :-


\sigma=√(np(1-p))\\\\=√(5(0.39)(1-0.39))\\\\=√(1.1895)=1.09064201276\approx1.09064201276\approx1.09

Hence, the standard deviation for x= 1.09

User Krohit
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