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How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl?
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How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl?

User KWriter
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Answer:ANSWER

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How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh-example-1
User Spoko
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Answer: Correct answer is 507g FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe(OH)2 / 1 mol FeCl2) x (89.8 g Fe(OH)2/ 1 mol Fe(OH)2) = 359 g Fe(OH)2.
User Davut
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