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Write the equation in slope-intercept form for the line that passes through the given pointand is perpendicular to the given equation.x + 3y = 6and passes through (-1, -6)

User Abhishek AN
by
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1 Answer

5 votes
5 votes

When 2 lines are perpendicular, the product of the slopes is equal to -1

Given x + 3y = 6

3y = -x + 6

y = -x/3 + 2

The slope is -1/3

Hence the slope of the line perpendicular to this

= -1/-1/3

= 3

Hence the equation of the line

y - -6 = 3(x - -1)

y + 6 = 3(x + 1)

y + 6 = 3x + 3

y = 3x + 3 - 6

y = 3x -3

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