Question

If h(x) = x − 1 and j(x) = −4x, solve h[j(5)] and select the correct answer below. (1 point) −21 −20 −19 −16

Answer 1

(h○j)(x)=h(j(x))

(h○j)(x)=-4x-1

(h○j)(5)=-4(5)-1

(h○j)(5)=-20-1

(h○j(5)=-21

Answer 2

first find what j(5) is
j(5)=-4(5)=-20

so
h(j(5))=h(-20)=-20-1=-21