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5 votes
If h(x) = x − 1 and j(x) = −4x, solve h[j(5)] and select the correct answer below. (1 point) −21 −20 −19 −16

2 Answers

1 vote
(h○j)(x)=h(j(x))

(h○j)(x)=-4x-1

(h○j)(5)=-4(5)-1

(h○j)(5)=-20-1

(h○j(5)=-21
User Techie
by
8.4k points
6 votes
first find what j(5) is
j(5)=-4(5)=-20

so
h(j(5))=h(-20)=-20-1=-21
User William Edmondson
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8.0k points