134k views
5 votes
an online coupon service has 13 offers for free samples, how many different request are possible if a customer request up to 3 free samples

User Akela
by
7.7k points

2 Answers

1 vote

Final answer:

To find the number of different requests possible if a customer can request up to 3 free samples out of 13 offers, use the formula for combinations without repetition: nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items selected.

Step-by-step explanation:

To find the number of different requests possible if a customer can request up to 3 free samples out of 13 offers, we will use the concept of combinations. Since the order of the samples does not matter, we will use combinations without repetition.

The formula for combinations without repetition is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items selected. In this case, n = 13 (number of offers) and r can be 1, 2, or 3 (number of free samples requested).

Therefore, the number of different requests possible for 1 free sample is 13C1 = 13! / (1!(13-1)!). Similarly, the number of different requests possible for 2 free samples is 13C2 = 13! / (2!(13-2)!), and the number of different requests possible for 3 free samples is 13C3 = 13! / (3!(13-3)!).

User Roman Alexander
by
7.1k points
3 votes
10 I think cause if they have 13 in total & ask for 3 then 13-3=10
User Gagik Sukiasyan
by
6.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.