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How many solutions does this linear equation have? Y= 2x - 5

-8x - 4y = -20

Please only answer if you know.

2 Answers

1 vote
y = 2x - 5...slope = 2, y int = -5

-8x - 4y = -20
-4y = 8x - 20
y = -2x + 5....slope = -2, y int = 5

different slopes, different y int's means 1 solution <==

** same slope, same y int = infinite solutions
** same slope, different y int's = no solutions

User Rstackhouse
by
8.0k points
5 votes

Answer:

Our given system has exactly one solution.

Explanation:

We have been given a system of equation. We are asked to find the number of solutions for our given system.

First of all, we will convert our second equation in slope-intercept form of equation as shown below:


-8x-4y=-20

Upon dividing both sides of our equation by -4, we will get:


(-8x)/(-4)-(4y)/(-4)=(-20)/(-4)


2x+y=5


2x-2x+y=-2x+5


y=-2x+5

Upon comparing our both equations, we can see that they have different slopes and different y-intercepts, therefore, they will have exactly one solutions as they will intersect at one place.

Upon looking at our attachment, we can see that our explanation is correct.

How many solutions does this linear equation have? Y= 2x - 5 -8x - 4y = -20 Please-example-1
User Niklas Berglund
by
7.3k points