Question

Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?

4x + 8
2x + 12
x^2 − 4
x^2 − 16

Answer 1

x^2-4 will be the answer ..

as denominator must not be zero to get a valid answer.

hope it helps

Answer 2

`x^2-4`

Explanation:

Sally found that a solution of x = 2 was extraneous for her function.

Extraneous solution is a solution that makes the denominator 0

Possible denominator are given . LEts plug in 2 for x and check which option gives us 0

`4x+8=4(2)+8= 16`

`2x+12=2(2)+12=4+12= 16`

`x^2-4= (2)^2-4= 4-4=0`

`x^2-16= (2)^2-16= 4-16= 12`

`x^2-4` gives us 0 when we plug in 2 for x.

So x=2 was extraneous solution for
`x^2-4`