Question

A ball of radius 0.200 m rolls with a constant linear speed of 3.00 m/s along a horizontal table. the ball rolls off the edge and falls a vertical distance of 2.08 m before hitting the floor. what is the angular displacement of the ball while the ball is in the air

Answer 1

Falling off the table the vertical distance doesn't depend on the horizontal velocity. Then the table height of 2.08 = (1/2)at^2 = 16t^2. t= 0.36 seconds to hit the floor.
During this time the velocity = 3x0.36 = 1.08 meters.
The angle it hits the floor is arcTan(2.08/1.08) = 62.6 degrees.