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Solve the inequality. Check your solutions.

7−(2/b)<(5/b)

im not surehow to answer this, it's supposedly in a number form but I'mcompetely lost. Maybe a _

User Sagar Giri
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1 Answer

7 votes
The inequality is


7- (2)/(b)\ \textless \ (5)/(b)

write 7 as 7b/b to have all the expressions in common denominator:


(7b)/(b) - (2)/(b)\ \textless \ (5)/(b)


(7b-2)/(b) \ \textless \ (5)/(b)


(7b-2)/(b)- (5)/(b)\ \textless \ 0


(7b-2-5)/(b)\ \textless \ 0


(7b-7)/(b)\ \textless \ 0


(7(b-1))/(b)\ \textless \ 0

here b=1 is a root and b=0 is not in the domain of the expression, but it still has an effect in the sign of the expression.

the sign table of
(7(b-1))/(b) is :

+++++++[0] --------[1] +++++

this means that for values of b to the left of 0 and to the right of 1, the expression is positive, and for values of b in (0, 1), the expression is negative.

that is
(7(b-1))/(b)\ \textless \ 0 for b∈(0, 1)

Answer: (0, 1)
User Idonnie
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