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Santtu Pajukanta · Answer 1 · 2018-12-08T17:17:22+0000

check the picture below.

the quadrilateral is a parallelogram, thus the diagonals bisect each other, so, we could have used either diagonal, and get the same midpoint.

$\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) B&({{ 4}}\quad ,&{{ 5}})\quad % (c,d) D&({{ -3}}\quad ,&{{ -3}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left(\cfrac{{{ -3+4}} }{2}\quad ,\quad \cfrac{-3+5}{2} \right)$

Quadrilateral ABCDABCD has vertices AA (-2, 2), BB (4, 5), CC (3, 0) and DD (-3, -3). What-example-1

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