Question

Simplify 7x+42/x^2+13+42

Answer 1

First you will need to add 13 and 42. Which equals 55. Using the equation a=a/1, convert the expression into a fraction. Where you will get 7x/1+42/x^2+55/1. Expand the fraction to get the least common denominator (X^2•7x/x^2•1 + 42/x^2 + x^2•55/x^2•1). Calculate the product (x^2•7x)= 7x^3. Remember that any expression multiplied by one remains the same (x^2•1)= x^2. Used the commutative property to reorder the terms of (x^2•55)= 55x^2. (7x^3/x^2 + 42/x^2 + 55x^2/x^2)
Then you will write all the numerators above the common denominator.

The answer will be 7x^3+42+55x^2/ x^2

Answer 2

First let's factor the bottom
= (x+7)(x+6)

So now the equation is 7x+42/(x+7)(x+6)
Now factor out the 6 on top

7x+42= 7(x+6)

Now equation is 7(x+6)/(x+7)(x+6)

The (x+6) will cancel out and your left with the answer

= 7/x+7