Question

The index of refraction for the compound benzene is 1.50. What is the speed of light in benzene?

Answer 1

The speed of light in benzene is 2.00 × 10⁸ m/s.

Step-by-step explanation:

The speed of light in a medium can be calculated using the formula

v = c / n

where v is the speed of light in the medium, c is the speed of light in a vacuum, and n is the refractive index of the medium.

In this case, the refractive index of benzene is given as 1.50. Since the speed of light in a vacuum is approximately 3.00 × 10⁸ m/s, we can calculate the speed of light in benzene.

v = (3.00 × 10⁸ m/s) / 1.50 = 2.00 × 10⁸ m/s

Therefore, the speed of light in benzene is 2.00 × 10⁸ m/s.

Answer 2

Given

The index of refraction is n=1.50

To find

What is the speed of light in benzene?

Explanation

Let the speed of light in benzene be v

The speed of light in vaccum be

`c=3*(10^8m)/(s)`

Thus ,

`\begin{gathered} v=(c)/(n) \\ \Rightarrow v=(3*10^8)/(1.5) \\ \Rightarrow v=2*10^8\text{ m/s} \end{gathered}`

Conlusion

The speed of light in benzene is

`2*10^8\text{ m/s}`