Question

What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=118y−5x=11?

Answer 1

8y−5x=11
8y = 5x + 11
y = 5/8x + 11/8 has slope = 5/8
a line that is perpendicular to the line, slope is opposite and reciprocal so slope = - 8/5

answer
slope = -8/5

Answer 2

The slope of a line that is perpendicular to the line whose equation is
`8y-5x=11` is
`m=-(8)/(5)`

Explanation:

Given : Equation
`8y-5x=11`

To find : What is the slope of a line that is perpendicular to the line whose equation is given?

Solution :

First we find the slope of the given line,

The general slope form of line is
`y=mx+b` where m is the slope of the line and b is the y-intercept.

Re-write the given equation into general form,

`8y-5x=11`

Take 5x to another side,

`8y=5x+11`

Divide both side by 8,

`y=(5)/(8)x+(11)/(8)`

On comparing with general form,

The slope of the line is
`m=(5)/(8)`

We know,

When two line are perpendicular one slope is negative reciprocal of another.

If the slope of line is
`m=(5)/(8)`

Then the slope of perpendicular line on this line is
`m=-(8)/(5)`

Therefore, The slope of a line that is perpendicular to the line whose equation is
`8y-5x=11` is
`m=-(8)/(5)`