Solving simultaneous equations by algebraic methods 3a+4x=29 2a-3x=-9

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asked Mar 28, 2018 206k views

1 Answer

Dalton Conley · Answer 1 · 2018-04-01T08:31:22+0000

3a+4x=29 (1st)
2a-3x=-9 (2nd)

multiply (1st) by 3 and (2nd) by 4

9a + 12x = 87 (1st)
8a - 12x = -36 (2nd)
---------------------add
17a = 51
a = 3

2a-3x=-9
2(3)-3x=-9
6 - 3x = -9
-3x = -15
x = 5

answer
x = 5 and a = 3

Solving simultaneous equations by algebraic methods 3a+4x=29 2a-3x=-9

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