Question

The Kc for the following reaction at 225 ∘C is 1.7×102. 3H2(g)+N2(g)⇌2NH3(g)

If the equilibrium mixture contains 0.15 M H2 and 0.017 M N2, what is the molar concentration of NH3?

I have no idea what I am doing wrong here, help!

Answer 1

Molar concentration of ammonia gas is 0.0987 M.

Step-by-step explanation:

Concentration of hydrogen gas =
`[H_2]=0.15 M`

Concentration of nitrogen gas =
`[N_2]=0.017 M`

Concentration of ammonia gas =
`[NH_3]=x`

Equilibrium constant of the reaction =
`K_c=1.7* 10^2`

`K_c=([NH_3]^2)/([H_2]^3* [N_2])`

`1.7* 10^2=(x^2)/((0.15 M)^3* (0.017 M))`

`9.5737* 10^(-3) M^2=x^2`

x = 0.0987 M

Molar concentration of ammonia gas is 0.0987 M.