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5 pennies ,3 dimes and 4 quarters are placed in a bag .what is the probability of selecting a quarter and then another quarter, given the first coin is not returned to the back after it is drawn? A. 2/11 B. 1/11 C. 1/22 D. 5/33

User Rick Davin
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1 Answer

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5+3+4 = 12 total coins

4 are quarters so first selection = 4/12 reduces to 1/3

after taking a coin out there would be 11 coins left and 3 quarters left

so 2nd selection would be 3/11

now multiply 3/11 x 1/3 = 3/33 which reduces to 1/11

B. 1/11 is the correct answer

User Alexey Chernikov
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8.2k points
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