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A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

User RRiVEN
by
7.7k points

2 Answers

5 votes

Answer:

2400

Explanation:

Given : The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each.

To Find: If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

Solution:

No. of faces of first die = 6

No. of faces of second die = 4

No. of faces of third die = 10

No. of faces of fourth die = 10

Now we are supposed to find the the number of possible outcomes exist.

So, Number of possible outcomes if all the dice are thrown together :

=
6 * 4 * 10 * 10

=
2400

Hence there are 2400 possible outcomes if all the dice are thrown together and their combination dictates a certain outcome of the game.

User Corina
by
9.1k points
0 votes
6 x 4 x 10 x 10 = 2400 possible outcomes
User PaulCK
by
7.9k points
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