Question

For the weak acid ch3cooh (acetic acid) that is titrated with a strong base (naoh), what species (ions/molecules) are present in the solution at the stoichiometric point?

Answer 1

At the stoichiometric point of the titration of acetic acid with a strong base, the species present in the solution are acetate ions (CH3COO-) and water (H2O).

Step-by-step explanation:

During the titration of acetic acid (CH3COOH) with a strong base (NaOH), at the stoichiometric point all of the acetic acid will have reacted with the sodium hydroxide. This means that the species present in the solution at the stoichiometric point are the acetate ions (CH3COO-) and water (H2O). The balanced chemical equation for the reaction is:

CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)

Answer 2

This is a strong base / week acid reaction.

NaOH + CH3COOH

The equilibrium of this reaction is very displaced to the right leading to the formation of the products

Na CH3COO + H2O

Na CH3COOH is a ionic compound which in solutionn will be as Na (+) and CH3COOH(-)

=> CH3COOH + NaOH = CH3 COO(-) + Na(+) + H2O

So, the predominant species in the solution are the ions Na(+) and CH3COO(-).

In general, in an strong base / weak acid titration, the predominant species present at the stoichiometric point will be the cation of the strong base (Na+ in this case) and the conjugate base of the weak acid (the anion of the weak acid, which is CH3COO- in this case).

The answer is predominantly Na(+) and CH3COO(-); predominantly because it is an equlibrium which means that the rectants will also br present.