Answer with explanation:
Vertices of ∆ABC are A (2,5), B (4,6) and C (3,1).
Plotting the points on coordinate plane
a.→

We have to find vertices of image , that is ΔA'B'C' when ∆ABC is reflected across x axis.
The Distance from each of the vertices of ∆ABC from X axis will be same as Perpendicular distance from each of vertices of ∆A'B'C' from X axis.
Result is shown in the image 1.
b.→

We have to find the image of vertices of triangle through line, y=3.
The Distance from each of the vertices of ∆ABC from line,y=3 will be same as Perpendicular distance from each of vertices of ∆A'B'C' from line, y=3.
Result is shown in the image 2.
c. →T(-2,5)
Translation of vertices of triangle ABC by 2 units left and 5 units up.

d.→T(3,-6)
Translation of vertices of triangle ABC by 3 units right and 6 units left.

e.→Rotation by 90° with respect to Origin
When rotated in clockwise direction ,vertices of ΔABC changes by the rule ,that is (x,y)→(y,-x) and in anticlockwise direction ,(x,y)→(-y,x).
In clockwise direction
A(2,5)→A"(5,-2)
B(4,6)→B"(6,-4)
C(3,1)→C"(1,-3)
In Anti clockwise direction
A(2,5)→A'(-5,2)
B(4,6)→B'(-6,4)
C(3,1)→C'(-1,3)
Image is depicted below.