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Find the equation of the circle with center at (-2,1) and passes through the point (3,1) .
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2 votes
Find the equation of the circle with center at

(-2,1)
and passes through the point
(3,1)
.

User Fariborz Ghavamian
by
8.6k points

1 Answer

5 votes
Radius (R) is equal to the distance between the points (-2,1) and (3,1)
R² = (-2 - 3)² + (1 - 1)² = (-5)² + 0 = 25
R = 5

Equation of the circle:
(х-(-2))² + (у-1)² = 5²
(х+2)² + (у-1)² = 25
User Mkmurray
by
8.1k points
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